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Answer :
We are given the height function
[tex]$$
h(x) = -16x^2 + 20x + 5,
$$[/tex]
where [tex]$x$[/tex] represents the time in seconds after the object is thrown, and [tex]$h(x)$[/tex] gives the height in feet.
To determine the height of the object at 1.4 seconds, we substitute [tex]$x = 1.4$[/tex] into the function:
[tex]$$
h(1.4) = -16(1.4)^2 + 20(1.4) + 5.
$$[/tex]
Following the order of operations:
1. First, calculate [tex]$(1.4)^2$[/tex].
2. Multiply the result by [tex]$-16$[/tex].
3. Then, compute [tex]$20 \times 1.4$[/tex].
4. Finally, add these results to the constant term [tex]$5$[/tex].
After performing these calculations, we find that
[tex]$$
h(1.4) \approx 1.64.
$$[/tex]
This means that 1.4 seconds after the object is thrown, its height is approximately 1.64 feet.
Thus, the correct interpretation is:
A. The height of the object 1.4 seconds after being thrown straight up in the air is 1.64 feet.
[tex]$$
h(x) = -16x^2 + 20x + 5,
$$[/tex]
where [tex]$x$[/tex] represents the time in seconds after the object is thrown, and [tex]$h(x)$[/tex] gives the height in feet.
To determine the height of the object at 1.4 seconds, we substitute [tex]$x = 1.4$[/tex] into the function:
[tex]$$
h(1.4) = -16(1.4)^2 + 20(1.4) + 5.
$$[/tex]
Following the order of operations:
1. First, calculate [tex]$(1.4)^2$[/tex].
2. Multiply the result by [tex]$-16$[/tex].
3. Then, compute [tex]$20 \times 1.4$[/tex].
4. Finally, add these results to the constant term [tex]$5$[/tex].
After performing these calculations, we find that
[tex]$$
h(1.4) \approx 1.64.
$$[/tex]
This means that 1.4 seconds after the object is thrown, its height is approximately 1.64 feet.
Thus, the correct interpretation is:
A. The height of the object 1.4 seconds after being thrown straight up in the air is 1.64 feet.
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