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Consider the reaction below. If you start with 5.00 moles of [tex]C_3H_8[/tex] (propane) and 5.00 moles of [tex]O_2[/tex], how many moles of carbon dioxide can be produced?

Answer :

The balanced equation for the reaction is:
C3H8 + 5O2 -> 3CO2 + 4H2O


According to the equation, for every 1 mole of C3H8, 3 moles of CO2 are produced. Therefore, with 5.00 moles of C3H8, we can produce:
5.00 moles C3H8 x 3 moles CO2/1 mole C3H8 = 15.0 moles CO2
However, we also need to consider the amount of O2 available. Since the stoichiometric ratio of C3H8 to O2 is 1:5, we would need 25.0 moles of O2 to fully react with 5.00 moles of C3H8. But we only have 5.00 moles of O2, so we are limited by the amount of O2 available. Therefore, we can only produce:
5.00 moles O2 x 3 moles CO2/5 moles O2 = 3.00 moles CO2
Therefore, with 5.00 moles of C3H8 and 5.00 moles of O2, we can produce a maximum of 3.00 moles of CO2.
Now, we can find the moles of CO2 produced using the stoichiometry of the balanced equation:
5.00 moles O2 x (3 moles CO2 / 5 moles O2) = 3.00 moles CO2
So, 3.00 moles of carbon dioxide can be produced in this reaction.

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