Answer :

To find the mass in grams of 1.64 moles of NaNO₂, we need to follow these steps:

1. Determine the Molar Mass of NaNO₂:
- Sodium (Na) has an atomic mass of approximately 22.99 g/mol.
- Nitrogen (N) has an atomic mass of approximately 14.01 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol, and since there are two oxygen atoms in NaNO₂, we multiply this by 2.

Therefore, the molar mass of NaNO₂ (Sodium Nitrite) can be calculated as:
[tex]\[
\text{Molar mass of NaNO₂} = 22.99 + 14.01 + (16.00 \times 2) = 69.0 \text{ g/mol}
\][/tex]

2. Calculate the Mass of 1.64 Moles of NaNO₂:
- Now that we have the molar mass, we can use it to find the mass of 1.64 moles of NaNO₂ using the formula:

[tex]\[
\text{Mass} = \text{Moles} \times \text{Molar Mass}
\][/tex]

Plug in the values:
[tex]\[
\text{Mass} = 1.64 \text{ moles} \times 69.0 \text{ g/mol} = 113.16 \text{ g}
\][/tex]

Therefore, the mass in grams of 1.64 moles of NaNO₂ is [tex]\(113.16\)[/tex] grams, which rounds to the option [tex]\(113.152\)[/tex] when matching with given choices.

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Rewritten by : Barada