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Answer :
The direction and magnitude of the resultant force is 7,870.1 lbs at 5.3 ° south of west.
What is the direction and resultant force?
We can start by breaking down the forces into their x and y components:
The force of 3700 lbs pulling west has an x-component of -3700 lbs and a y-component of 0 lbs.
The force of 4200 lbs pulling 10° north of west has an x-component of -4200 cos(10°) lbs and a y-component of 4200 sin(10°) lbs.
The x-component of the resultant force is;
Fx = -3700 lbs - 4200 cos(10°) lbs
Fx = -7,836.19 lbs
The y-component of the resultant force is;
Fy = 4200 sin(10°) lbs
Fy = 729.32 lbs
To find the magnitude and direction of the resultant force, we can use the Pythagorean theorem and inverse tangent function:
The magnitude of the resultant force is;
F = √(Fx² + Fy²)
F = √ (-7836.19² + 729.32²)
F = 7,870.1 lbs
The direction of the resultant force is;
θ = arc tan (Fy/Fx)
θ = arc tan (729.32 / 7836.19)
θ = 5.3⁰
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