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How many numbers are in the list 147, 144, 141, ..., 42, 39?

Answer :

Answer:

37

Step-by-step explanation:

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Final answer:

The sequence provided is an arithmetic sequence. Using the formula for the n-th term of an arithmetic sequence and given the first term, common difference, and last term, it's possible to calculate that there are 37 numbers in this sequence.

Explanation:

The list provided shows a sequence of numbers decreasing by 3 starting from 147 and ending at 39. This type of sequence is known as an arithmetic sequence. We can calculate the total numbers in such a sequence using the formula for the n-th term of an arithmetic sequence: a + (n-1)xd, where a is the first term, n is the number of terms, and d is the common difference. Here a=147, d=-3 (since each term decreases by 3), and the last term = 39. Solving the formula 147 + (n-1)*(-3) = 39, we find that n = 37. So, there are 37 numbers in this sequence.

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