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Are job applicants with easy-to-pronounce last names more likely to get called for an interview than applicants with difficult-to-pronounce last names?

A total of 535 job applications were sent out with easy-to-pronounce last names, and 866 identical job applications were sent out with difficult-to-pronounce last names. Out of these, 339 applicants with easy-to-pronounce names were called for an interview, while 520 applicants with difficult-to-pronounce names were called for an interview.

What can be concluded at the 0.01 level of significance?

The null and alternative hypotheses would be:

Answer :

The null and alternative hypotheses would be H0: p1 = p2 and Ha: p1 > p2, respectively.

The null hypothesis is that there is no difference in the likelihood of being called for an interview between applicants with easy to pronounce last names and applicants with difficult to pronounce last names. The alternative hypothesis is that there is a difference in the likelihood of being called for an interview between applicants with easy to pronounce last names and applicants with difficult to pronounce last names.

To test the null hypothesis, we can use a z-test for proportions. The z-statistic is calculated as follows:

z = (p1 - p2) / [tex]\sqrt{[/tex](p(1 - p) * (1 / n1 + 1 / n2))

where:

p1 is the proportion of applicants with easy to pronounce last names who were called for an interview

p2 is the proportion of applicants with difficult to pronounce last names who were called for an interview

n1 is the sample size of applicants with easy to pronounce last names

n2 is the sample size of applicants with difficult to pronounce last names

In this case, the z-statistic is calculated as follows:

z = (339 / 535 - 520 / 866) / [tex]\sqrt{[/tex]((1 / 535 + 1 / 866)) = 1.33

The p-value for the z-statistic is 0.183. This means that there is a 18.3% chance of obtaining a z-statistic of 1.33 or greater if the null hypothesis is true.

Since the p-value is greater than the significance level of α=0.01, we cannot reject the null hypothesis. Therefore, there is not enough evidence to conclude that there is a difference in the likelihood of being called for an interview between applicants with easy to pronounce last names and applicants with difficult to pronounce last names.

For this study, we should use a one-tailed z-test because we are only interested in the possibility that applicants with easy to pronounce last names are more likely to be called for an interview than applicants with difficult to pronounce last names.

The null and alternative hypotheses would be:

Null hypothesis: H0: p1 = p2

Alternative hypothesis: Ha: p1 > p2

To learn more about alternative hypotheses here:

https://brainly.com/question/32562440

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