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Answer :
Final answer:
To stop Manny's car from rolling down a hill with a 30° slope, we need to consider the gravitational force pulling the car downhill and the friction force opposing its motion. By calculating these forces, we find that the force required to stop the car is approximately 104 pounds.
Explanation:
To determine the force required to stop Manny's car from rolling down a hill, we need to consider the gravitational force pulling the car downhill and the friction force opposing its motion. The gravitational force can be calculated by multiplying the mass of the car (120 pounds) by the acceleration due to gravity (9.8 m/s²). The friction force can be calculated by multiplying the coefficient of friction between the car's tires and the road surface by the normal force.
Using trigonometry, we can determine that the normal force is equal to the weight of the car multiplied by the cosine of the angle of the slope, which is 30°. The coefficient of friction depends on the surfaces in contact, but let's assume a typical value of 0.8.
So, the normal force is 120 pounds * cos(30°) and the friction force is 0.8 * (120 pounds * cos(30°)). Adding these two forces together will give us the force required to stop the car.
After calculating the values, we find that the force required to stop Manny's car is approximately 104 pounds.
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