We appreciate your visit to What is the molarity of a solution prepared by diluting 35 8 mL of 6 5 M HCl to 250 0 mL A 0 28. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The molarity of the solution prepared by diluting 35.8 mL of 6.5 M HCl to 250.0 mL is 0.93 M. The correct option is b. 0.93 M .
The molarity of a solution after dilution can be determined using the equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution.
In the given problem, we have:
Initial molarity (M1) = 6.5 M
Initial volume (V1) = 35.8 mL
Final volume (V2) = 250.0 mL
Using the equation M1V1 = M2V2, we calculate the final molarity (M2) as follows:
M2 = (M1V1) / V2 = (6.5 M * 35.8 mL) / 250.0 mL = 0.93 M
The molarity of the diluted HCl solution is therefore 0.93 M. The correct option is b. 0.93 M .
Thanks for taking the time to read What is the molarity of a solution prepared by diluting 35 8 mL of 6 5 M HCl to 250 0 mL A 0 28. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
