High School

We appreciate your visit to Given A 2B 3C 5D rightarrow AH 35 What is AH for the reverse reaction decomposition of 10 mol of D A 70 B 17. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Given:

\[ A + 2B + 3C + 5D \rightarrow AH = +35 \]

What is \( AH \) for the reverse reaction (decomposition) of 10 mol of D?

A. +70
B. -17.5
C. +17.5
D. -70

Additional Information:

1. \[ \text{SO}_2(g) \rightarrow \text{S}(s) + \text{O}_2(g), \quad \Delta H = 296.1 \, \text{kJ} \]

2. \[ \text{SO}_3(g) \rightarrow \text{SO}_2(g) + \frac{1}{2} \text{O}_2(g), \quad \Delta H = 99.1 \, \text{kJ} \]

Find \( \Delta H \) for the following reaction:

\[ 2\text{S}(s) + 3\text{O}_2(g) \rightarrow 2\text{SO}_3(g) \]

Possible Answers:

A. -790.4 kJ
B. +97.9 kJ
C. +394.0 kJ
D. -394.0 kJ
E. -97.9 kJ

Answer :

The enthalpy change for the decomposition of 10 mol of is -350 kJ. So, the correct option is (D) -394.0 kJ because it is closely related

The first step is to write out the balanced chemical equations for the forward and reverse reactions. The forward reaction is:

A + 2B + 3 C -+5D

The reverse reaction is the decomposition of 10 mol of D, which is:

5D -+ A + 2B + 3 C

The enthalpy change for the reverse reaction is equal to the negative of the enthalpy change for the forward reaction. In other words, if the enthalpy change for the forward reaction is +35 kJ, then the enthalpy change for the reverse reaction is -35 kJ.

Therefore, the enthalpy change for the decomposition of 10 mol of D is -35 kJ/mol * 10 mol = -350 kJ.

Here is a more detailed explanation of each step:

Write out the balanced chemical equations for the forward and reverse reactions.

The forward reaction is:

A + 2B + 3 C -+5D

The reverse reaction is the decomposition of 10 mol of D, which is:

5D -+ A + 2B + 3 C

Determine the enthalpy change for the reverse reaction.

The enthalpy change for the reverse reaction is equal to the negative of the enthalpy change for the forward reaction. In other words, if the enthalpy change for the forward reaction is +35 kJ, then the enthalpy change for the reverse reaction is -35 kJ.

Therefore, the enthalpy change for the decomposition of 10 mol of D is -35 kJ/mol * 10 mol = -350 kJ.

The answer to the question is (D) -394.0 kJ because it is closely related.

To know more about enthalpy change refer here :

https://brainly.com/question/24277116#

#SPJ11

Thanks for taking the time to read Given A 2B 3C 5D rightarrow AH 35 What is AH for the reverse reaction decomposition of 10 mol of D A 70 B 17. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada