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Use the model for body surface area (BSA), given by the formula:

\[ \text{BSA} = \sqrt{\frac{wh}{3600}} \]

where \( w \) is the weight in kg and \( h \) is the height in cm.

Find the weight of a 176-cm male to the nearest kg, whose BSA is 2.3.

Answer :

Final answer:

To solve for the weight of a person given their body surface area and height, you need to rearrange the given formula and solve step by step for the unknown variable. For a 176-cm male with a body surface area of 2.3, the calculated weight is approximately 108 kg.

Explanation:

In this problem, you are given the formula to calculate the Body Surface Area (BSA) of a male, BSA = √wh/3600, where BSA is given as 2.3, h (height) is 176 cm and you are asked to solve for w (weight).

  1. First, insert the given BSA and height values into the equation so it reads BSA = √w(176)/3600 = 2.3;
  2. Next, square both sides of the equation to get rid of the square root on the left side:
  3. 5.29 (2.3²) = w(176)/3600;
  4. Multiply both sides of the equation by 3600 to solve for w:
  5. 19044.4 = w(176);
  6. Finally, divide both sides by 176 to solve for w:
  7. w = 108 approximately.

So, the weight of a 176-cm male with a BSA of 2.3 is approximately 108 kg.

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