High School

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The director of health services is concerned about a possible flu outbreak at her college. She surveyed 100 randomly selected residents from the college's dormitories to see whether they had received a preventative flu shot. The results are shown below.

What is the probability that a dormitory resident chosen at random from this group has had a flu shot, given that he is male?

**Residents At College Dormitories**

\[
\begin{tabular}{|c|c|c|c|}
\hline
& \text{Male} & \text{Female} & \text{Total} \\
\hline
\text{Had Flu Shot} & 39 & 41 & 80 \\
\hline
\begin{tabular}{c}
\text{Didn't Have} \\
\text{Flu Shot}
\end{tabular} & 12 & 8 & 20 \\
\hline
\text{Total} & 51 & 49 & 100 \\
\hline
\end{tabular}
\]

A. [tex]$\frac{51}{100}$[/tex]
B. [tex]$\frac{39}{100}$[/tex]
C. [tex]$\frac{39}{80}$[/tex]
D. [tex]$\frac{13}{17}$[/tex]

Answer :

To determine the probability that a dormitory resident chosen at random has had a flu shot, given that he is male, let’s follow these steps:

1. Identify the Total Number of Males:
From the table, the total number of males is 51.

2. Identify the Number of Males Who Had a Flu Shot:
From the table, the number of males who had a flu shot is 39.

3. Calculate the Probability:
The probability that a randomly chosen male dormitory resident has had a flu shot is given by the ratio of the number of males who received the flu shot to the total number of males.

[tex]\[ \text{Probability} = \frac{\text{Number of males who had a flu shot}}{\text{Total number of males}} \][/tex]

Plug in the values:

[tex]\[ \text{Probability} = \frac{39}{51} \][/tex]

4. Simplify the Fraction:
Simplifying [tex]\(\frac{39}{51}\)[/tex]:

[tex]\[ \frac{39 \div 3}{51 \div 3} = \frac{13}{17} \][/tex]

So, the simplified probability that a dormitory resident chosen at random has had a flu shot, given that he is male, is [tex]\(\frac{13}{17}\)[/tex].

Therefore, the correct answer is:

[tex]\[ \frac{13}{17} \][/tex]

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