High School

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Consider the expression and the variable:

- Simplify the expression: [tex]-4 \cdot 3m = -12[/tex]

Joaquin and Serena are exploring equations and inequalities and are wondering which are always true, no matter what value is chosen.

Regarding the following inequality, what could you tell them?

a. [tex]4s + 6 \geq 6 + 4s[/tex]

- What are the solutions to this inequality?
- How would you graph the solutions on a number line?

Answer :

To solve the inequality [tex]\(4s + 6 \geq 6 + 4s\)[/tex], let's work through it step by step:

1. Write down the inequality:
[tex]\(4s + 6 \geq 6 + 4s\)[/tex]

2. Simplify the inequality:
We'll start by getting the terms involving the variable [tex]\(s\)[/tex] on one side. We can do this by subtracting [tex]\(4s\)[/tex] from both sides of the inequality:
[tex]\[
4s + 6 - 4s \geq 6 + 4s - 4s
\][/tex]

3. Simplify the terms:
This simplifies to:
[tex]\[
6 \geq 6
\][/tex]

4. Interpret the simplified inequality:
The statement [tex]\(6 \geq 6\)[/tex] is true, because 6 is equal to 6. Since there is no variable [tex]\(s\)[/tex] present in the inequality anymore, it means the original inequality holds true for any value of [tex]\(s\)[/tex].

5. Conclusion about the solution:
This means that the inequality [tex]\(4s + 6 \geq 6 + 4s\)[/tex] is always true, no matter what value [tex]\(s\)[/tex] takes. Therefore, the solution is that [tex]\(s\)[/tex] can be any real number.

6. Graphing the solution on a number line:
Since [tex]\(s\)[/tex] can be any real number, we graph this by shading the entire number line, indicating that all real numbers are solutions.

In summary, the inequality [tex]\(4s + 6 \geq 6 + 4s\)[/tex] is true for all real numbers [tex]\(s\)[/tex]. The solution to this inequality is that any real number can be a value for [tex]\(s\)[/tex].

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