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11. The temperature of a 50 kg block increases by 15°C when337,500 J of thermal energy are added to the block. (Chapter5- Pages 141-142)a. What is the specific heat of the object? Show theappropriate equation from your book and show your workwith units.b. What is the block made of? Use the chart on page 141.c. Is this block a good material for insulators or conductors

11 The temperature of a 50 kg block increases by 15 C when337 500 J of thermal energy are added to the block Chapter5 Pages

Answer :

0.45 kJ/kg/°C is the specific heat of the object when the temperature of a 50 kg block increases by 15°C when337,500 J of thermal energy are added to the block.

Heat = mass × specific heat × change in temperature

q = m C ΔT

Given:

q = 337500 J

m = 50 kg

ΔT = 15°C

now, place values

337500 J = (50 kg) C (15°C)

C = 450 J/kg/°C

Specific heat is usually recorded in J/g/°C or kJ/kg/°C. Converting:

C = 0.45 J/g/°C = 0.45 kJ/kg/°C

the amount of heat needed to increase a substance's temperature by one degree Celsius in one gram, also known as specific heat. Typically, calories or joules per gram per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gram per degree Celsius.

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