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Two astronauts are floating motionless in space when they push off from each other.

If the 139 kg astronaut is moving away at 3 m/s, what is the magnitude of the momentum of the other astronaut (in kg m/s)?

Answer :

Final answer:

The magnitude of the momentum of the other astronaut is 417 kg m/s.

Explanation:

To find the magnitude of momentum of the other astronaut, we can use the law of conservation of momentum. The law states that the total momentum before a collision is equal to the total momentum after the collision when no external forces are involved. In this case, the momentum of the two astronauts before they push off from each other is zero, since they are motionless. Therefore, the total momentum after they push off from each other is also zero. Since one astronaut is moving away at a velocity of 3 m/s, the other astronaut must be moving towards him at the same velocity. Therefore, the magnitude of the momentum of the other astronaut is given by:

Momentum = mass × velocity

Momentum = 139 kg × (-3 m/s)

Momentum = -417 kg m/s

The magnitude of the momentum of the other astronaut is 417 kg m/s.

Learn more about Conservation of momentum here:

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