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The vapor pressure (at 25 °C) of benzene and toluene are 103.4 and 46.9 torr respectively. In a solution of 45.0 g of benzene and 55.0 g of toluene, what is the applied pressure?

(Benzene = C\(_6\)H\(_6\) = 78 g/mol, Toluene = C\(_7\)H\(_8\) = 92 g/mol)

a) 102.7
b) 36.3
c) 16.4
d) 169.0
e) 174.6
f) none

Answer :

The partial pressure of benzene and toluene is 74.11 torr.

Generally, vapor pressure is defined as a measure of the tendency of a material to change into the gaseous or vapor state, and it basically increases with temperature. Basically the temperature at which the vapor pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is known as the boiling point of the liquid.

Pa denotes the Vapor pressure of benzene = 103.4 torr

Pb denotes the Vapor pressure of toluene = 46.9 torr

Moles of benzene can be calculated by the formula,

Number of moles of benzene = Given mass of benzene / Molar mass of benzene = 45/78 = 0.57 moles

Number of moles of toluene = Given mass of toluene/ Molar mass of toluene = 55/92 = 0.59 moles

Mole fraction of benzene (Xa) = 0.57/(0.57+0.59) = 0.57 / 1.16 = 0.49

Mole fraction of toluene (Xb) = 0.59/(0.57+0.59) = 0.50

Partial pressure = (XaPa + XbPb)

= 0.49 × 103.4 + 0.50 × 46.9

= 50.666 + 23.45 = 74.11 torr

Learn more about partial pressure from the link given below.

https://brainly.com/question/13199169

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