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What is the volume in liters of 4.829 pounds of gold? The density of gold is 19.3 g/cm³.

Please express the answer in decimal form, not scientific notation.

Conversion factors:
- kilo = 10³
- milli = 10⁻³
- 1 cm³ = 1 mL
- 1 kg = 2.205 lbs

Answer :

Final answer:

The volume of 4.829 pounds of gold is approximately 0.00219 liters.

Explanation:

To calculate the volume of gold in liters, we need to convert the given mass from pounds to kilograms and then use the density of gold to find the volume in cubic centimeters (cm³). Finally, we can convert the volume from cm³ to liters.

First, let's convert the mass of gold from pounds to kilograms. We know that 1 kg is equal to 2.205 lbs, so:

Mass of gold in kg = 4.829 lbs * (1 kg / 2.205 lbs) = 2.190 kg

Next, we can use the formula for density to find the volume of gold in cm³:

Volume of gold in cm³ = Mass of gold in kg / Density of gold = 2.190 kg / 19.3 g/cm³

Now, we need to convert the volume from cm³ to liters. We know that 1 cm³ is equal to 1 mL, and 1 L is equal to 1000 mL, so:

Volume of gold in liters = Volume of gold in cm³ * (1 mL / 1 cm³) * (1 L / 1000 mL)

Calculating the volume:

Volume of gold in liters = 2.190 cm³ * (1 mL / 1 cm³) * (1 L / 1000 mL) = 0.00219 liters

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