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A solution is prepared by dissolving 23.7 g of \(\text{CaCl}_2\) in 375 g of water. The density of the resulting solution is 1.05 g/mL.

What is the concentration of \(\text{CaCl}_2\) by mass, and what is the volume of the solution in mL?

A) 5.94%, 380 mL
B) 5.94%, 399 mL
C) 0.0632%, 375 mL
D) 0.0594%, 0.399 mL

Answer :

The concentration of CaCl2​ is 5.94% by mass, and the volume of the solution is 399 mL.

To determine the concentration of CaCl2​ in the solution, we need to calculate the mass of CaCl2​ dissolved in the given solution.

Given:

Mass of CaCl2​ = 23.7 g

Mass of water = 375 g

Density of solution = 1.05 g/mL

The total mass of the solution can be calculated by adding the mass of CaCl2​ and the mass of water:

Total mass of solution = Mass of CaCl2​ + Mass of water = 23.7 g + 375 g = 398.7 g

Next, we can calculate the concentration of CaCl2​ as a percentage by mass:

Concentration of CaCl2​ = (Mass of CaCl2​ / Total mass of solution) × 100

Concentration of CaCl2​ = (23.7 g / 398.7 g) × 100 ≈ 5.94%

Therefore, the concentration of CaCl2​ in the solution is approximately 5.94% by mass.

The volume of the solution is given as 1.05 g/mL. We can calculate the volume of the solution using the formula:

Volume of solution = Total mass of solution / Density of solution

Volume of solution = 398.7 g / 1.05 g/mL ≈ 380 mL

Hence, the volume of the solution is approximately 380 mL.

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