We appreciate your visit to The lifting force tex F tex exerted on an airplane wing varies jointly as the area tex A tex of the wing s surface and. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The lifting force on the wing if the plane slows down to 190 miles per hour F'=708.53 N
What is force?
The force is an external agent applied to the body to displace it from its position .The force can be of different types lifting force, Frictional force, viscous force etc.
We have,
The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means that,
[tex]F=kAv^2[/tex]
k is constant
If, A = 190 Ft², v = 220 mph, F = 950 pounds
Let's find k first from above data. So,
[tex]k=\dfrac{F}{Av^2}[/tex]
k=950/190*220^2
k=0.0001033
It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,
F'=0.0001033×190×190^2
F'=708.53 pounds
So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.
To know more about Lifting force follow
https://brainly.com/question/2538403
Thanks for taking the time to read The lifting force tex F tex exerted on an airplane wing varies jointly as the area tex A tex of the wing s surface and. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
Answer:
F'=708.53 N
Explanation:
We have,
The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,
[tex]F=kAv^2[/tex]
k is constant
If, A = 190 Ft², v = 220 mph, F = 950 pounds
Let's find k first from above data. So,
[tex]k=\dfrac{F}{Av^2}\\\\k=\dfrac{950}{190\times 220^2}\\\\k=0.0001033[/tex]
It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,
[tex]F'=0.0001033\times 190\times (190)^2\\\\F'=708.53\ \text{pounds}[/tex]
So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.
