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Answer :
Final answer:
To find the force applied to the handle of the suitcase, we can use the concept of equilibrium in physics. The force applied to the handle can be broken down into horizontal and vertical components, and the horizontal component can be calculated using trigonometry. Using the given normal force and the angle, we can determine that the force applied to the handle is approximately 192.74 N.
Explanation:
To find the force applied to the handle of the suitcase, we can use the concept of equilibrium in physics. Since the suitcase is being pulled with constant speed, we know that the net force acting on it is zero. The force applied to the handle can be broken down into horizontal and vertical components. The vertical component is equal to the weight of the suitcase, which is the product of its mass and the acceleration due to gravity. The horizontal component is determined by the angle of the handle.
Using trigonometry, we can find that the horizontal component of the force applied to the handle is given by F * cos(angle), where F is the total force applied to the handle. Since the net force is zero, the vertical component of the force applied to the handle should equal the normal force acting on the suitcase. Therefore, we can calculate the horizontal component of the force applied to the handle using the equation:
F * cos(angle) = normal force
Solving for F, we get:
F = normal force / cos(angle)
Plugging in the given values:
F = 170 N / cos(25 degrees)
Calculating this, we find that the force applied to the handle is approximately 192.74 N.
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