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Answer :
To produce 35.5 grams of KCl, you need 0.476 moles of KCIO₃.
To solve this problem, we first need to understand the stoichiometric relationship between KCIO₃ and KCl in the given reaction: 2 KCIO₃ → 2 KCl + 3 O₂.
- Calculate the molar mass of KCl: K (39.1 g/mol) + Cl (35.45 g/mol) = 74.55 g/mol.
- Calculate the moles of KCl in 35.5 grams: 35.5 g / 74.55 g/mol ≈ 0.476 moles of KCl.
- Using the stoichiometric ratio from the balanced equation (2 moles of KCIO₃ produce 2 moles of KCl), the moles of KCIO₃ required will be the same as the moles of KCl.
- Therefore, 0.476 moles of KCIO₃ are required to produce 35.5 grams of KCl.
0.476 moles of KCIO₃ are required to produce 35.5 grams of KCl based on stoichiometric calculations.
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