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Answer :
Final answer:
To find the mass of Au produced, balance the equation and use stoichiometry. 0.0500 mol of Au₂S₃ would produce 19.7 g of Au.
Explanation:
In order to determine the mass of Au produced, we need to balance the equation for the reaction and use stoichiometry. The balanced equation for the reaction is:
Au₂S₃ + 6H₂ → 2Au + 3H₂S
From the balanced equation, we can see that 1 mol of Au₂S₃ produces 2 mol of Au. Therefore, for 0.0500 mol of Au₂S₃, the mass of Au produced would be:
(0.0500 mol Au₂S₃) x (2 mol Au / 1 mol Au₂S₃) x (197 g Au / 1 mol Au) = 19.7 g Au
So the correct answer is B. 19.7 g.
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