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Answer :
Answer:
12 inches.
Step-by-step explanation:
Did the question, got it right.
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Rewritten by : Barada
I can get it into standard form of that certain conic section by completing the square
(x^2-2x)+(y^2-4y)-31=0
(x^2-2x+1-1)+(y^2-4y+4-4)-31=0
(x-1)^2-1+(y-2)^2-4-31=0
(x-1)^2+(y-2)^2-36=0
(x-1)^2+(y-2)^2=36
(x-1)^2+(y-2)^2=6^2
in form
(x-h)^2+(y-k)^2=r^2
r=radius
so how wide it is is the diameter which is 2 times of radius
6=radius
6 times 2=12
12 inches I assume if the units in equation is in inches
(x^2-2x)+(y^2-4y)-31=0
(x^2-2x+1-1)+(y^2-4y+4-4)-31=0
(x-1)^2-1+(y-2)^2-4-31=0
(x-1)^2+(y-2)^2-36=0
(x-1)^2+(y-2)^2=36
(x-1)^2+(y-2)^2=6^2
in form
(x-h)^2+(y-k)^2=r^2
r=radius
so how wide it is is the diameter which is 2 times of radius
6=radius
6 times 2=12
12 inches I assume if the units in equation is in inches
