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Consider two 5 L chambers. In one, there are 5.00 g of [tex]O_2[/tex], and in the other, there are 5.00 g of He. Which has the higher pressure at room temperature?

Answer :

The gas having higher pressure at room temperature, is P = 6.11 atm.

What is the ideal gas law?

The general gas equation, often known as the ideal gas law, is the equation of state for a hypothetical ideal gas. It has a number of limitations, but it provides a decent approximation of the behavior of numerous gases under various circumstances.

According to the ideal gas equation,

PV =nRT

For O₂,

Number of moles of oxygen gas = 5.00 g /32 g/mol = 0.156 moles

P =?

V = 5 L

n = 0.156 moles

T = 25 + 273 = 298 K

R = 0.082 atmLK-1mol-1

P = nRT/V

P = 0.156 moles × 0.082 atmLK-1mol-1 × 298 K/5 L

P = 0.76 atm

For He,

Number of moles of He = 5/4 g/mol = 1.25 moles

P =?

V = 5 L

n = 1.25 moles

T = 25 + 273 = 298 K

R = 0.082 atmLK-1mol-1

P = nRT/V

P =1.25 moles × 0.082 atmLK-1mol-1 × 298 K/5 L

P = 6.11 atm

Hence the gas having higher pressure at room temperature is He.
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