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Answer :
The new temperature in degrees Celsius, when the volume increases to 4.3 L and the pressure increases to 776.2 mm Hg, is approximately option D. 211.75 °C.
By applying the combined gas law, we can calculate the new temperature. The combined gas law takes into account the changes in pressure, volume, and temperature of a gas sample. Using the given values, we substitute them into the formula and perform the necessary calculations to find T2.
To solve this problem, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law is expressed as:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
Given:
P1 = 749.5 mm Hg
V1 = 2.8 L
T1 = 31.2 °C
V2 = 4.3 L
P2 = 776.2 mm Hg
We need to find T2, the final temperature.
Rearranging the equation, we have:
T2 = (P2 * V2 * T1) / (P1 * V1)
Substituting the given values:
T2 = (776.2 * 4.3 * 31.2) / (749.5 * 2.8)
T2 ≈ 211.75 °C
Therefore, the new temperature in degrees Celsius is approximately 211.75 °C.
The new temperature in degrees Celsius, when the volume increases to 4.3 L and the pressure increases to 776.2 mm Hg, is approximately 211.75 °C.
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