Answer :

Final answer:

To calculate the mass of sodium acetate needed for a 13.6% solution, multiply 30 g (volume of solution) by 0.136. Follow the steps detailed for preparing the buffer solution.

Explanation:

To calculate the mass of sodium acetate needed to make 30 mL of a 13.6% sodium acetate solution, we have to find the mass that corresponds to 13.6% of the total solution mass. First, we convert the percentage to a decimal (0.136), then we multiply it by the required volume of solution in grams (since 1 mL of water is approximately equal to 1 g, so 30 mL is 30 g for the purpose of this calculation). Therefore, the calculation is 30 g solution × 0.136 = mass of sodium acetate.

The mass of sodium acetate trihydrate, CH₃COONa·3H₂O, can be found by using its molar mass calculated from the atomic masses: Na (23.0), H (1.0), C (12.0), and O (16.0).

Buffer Preparation

Transfer the sodium acetate into a 50 mL conical tube.

Add about 20 mL of DI water into the conical tube.

Secure the cap on the tube and invert to mix the contents until the solute is completely dissolved.

Pour out all of the solution into a 50 mL graduated cylinder.

Add DI water to bring the total volume to 30.0 mL.

Transfer all of the solution back into your 50 mL conical tube and secure the cap.

Invert the tube several times to thoroughly mix the contents.

Label the tube with contents (13.6% Sodium Acetate), initial, and date.

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Rewritten by : Barada