High School

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Gas Laws Fact Sheet

[tex]
\[
\begin{tabular}{|l|l|}
\hline
\text{Ideal gas law} & P V = n R T \\
\hline
\text{Ideal gas constant} & \begin{tabular}{l}
R = 8.314 \left[\frac{L \cdot kPa}{mol \cdot K}\right] \\
\text{or} \\
R = 0.0821 \frac{L \cdot atm}{mol \cdot K}
\end{tabular} \\
\hline
\text{Standard atmospheric pressure} & 1 \, atm = 101.3 \, kPa \\
\hline
\text{Celsius to Kelvin conversion} & K = {}^{\circ} C + 273.15 \\
\hline
\end{tabular}
\]
[/tex]

Select the correct answer.

The gas in a sealed container has an absolute pressure of 125.4 kilopascals. If the air around the container is at a pressure of 99.8 kilopascals, what is the gauge pressure inside the container?

A. 15 kPa
B. 24.1 kPa
C. 25.6 kPa
D. 1126 kPa
E. 2252 kPa

Answer :

To solve this problem, we need to find the gauge pressure inside the container. Gauge pressure is the difference between the absolute pressure inside the container and the atmospheric pressure outside. Here's how you can determine that step-by-step:

1. Identify the Absolute Pressure:
The absolute pressure inside the container is given as 125.4 kilopascals (kPa).

2. Identify the Atmospheric Pressure:
The atmospheric pressure, which is the pressure outside the container, is given as 99.8 kilopascals (kPa).

3. Apply the Formula for Gauge Pressure:
The gauge pressure can be calculated using the formula:
[tex]\[ \text{Gauge Pressure} = \text{Absolute Pressure} - \text{Atmospheric Pressure} \][/tex]

4. Perform the Calculation:
Substitute the given values into the formula:
[tex]\[ \text{Gauge Pressure} = 125.4 \, \text{kPa} - 99.8 \, \text{kPa} \][/tex]
[tex]\[ \text{Gauge Pressure} = 25.6 \, \text{kPa} \][/tex]

Therefore, the gauge pressure inside the container is 25.6 kilopascals. The correct answer from the given choices is C. 25.6 kPa.

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Rewritten by : Barada