High School

We appreciate your visit to Given that Neuron X has equilibrium potential values of tex E NA 50 text mV tex tex E K 90 text mV tex and tex. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Given that Neuron X has equilibrium potential values of [tex]E_{NA} = 50\, \text{mV}[/tex], [tex]E_{K} = -90\, \text{mV}[/tex], and [tex]E_{Cl} = -55\, \text{mV}[/tex], if Neuron X had a [tex]G_{Na}[/tex] that was 100 times as large as either [tex]G_{K}[/tex] or [tex]G_{Cl}[/tex], what would be the approximate value of the resting membrane potential ([tex]V_{m}[/tex])?

A. -90 mV
B. -55 mV
C. 50 mV

Answer :

Final answer:

The approximate value of the resting membrane potential (Vm) for Neuron X is approximately 47.55mV.

Explanation:

The resting membrane potential of a neuron is determined by the equilibrium potentials of the ions and their permeabilities. In this case, Neuron X has equilibrium potential values of ENA = 50mV, EK = -90mV, and ECl = -55mV.

Given that Neuron X has a GNa that is 100 times as large as either GK or GCl, it means that the permeability of the membrane to sodium ions (Na+) is much higher compared to potassium ions (K+) and chloride ions (Cl-).

The resting membrane potential (Vm) can be approximated using the Goldman-Hodgkin-Katz equation, which takes into account the equilibrium potentials and permeabilities of the ions:

Vm = (PNa * ENa + PK * EK + PCl * ECl) / (PNa + PK + PCl)

Since GNa is 100 times larger than GK or GCl, we can assume that the permeability of Na+ (PNa) is 100 times larger than PK or PCl. Therefore, the equation can be simplified to:

Vm = (100 * ENa + EK + ECl) / (100 + 1 + 1)

Substituting the given values, we get:

Vm = (100 * 50mV + (-90mV) + (-55mV)) / (100 + 1 + 1)

Vm = (5000mV - 90mV - 55mV) / 102

Vm = 4855mV / 102

Vm ≈ 47.55mV

Therefore, the approximate value of the resting membrane potential (Vm) for Neuron X is approximately 47.55mV.

Learn more about resting membrane potential here:

https://brainly.com/question/33730682

#SPJ14

Thanks for taking the time to read Given that Neuron X has equilibrium potential values of tex E NA 50 text mV tex tex E K 90 text mV tex and tex. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada

Final answer:

The approximate value of the resting membrane potential (Vm) for Neuron X is approximately 47.55mV.

Explanation:

The resting membrane potential of a neuron is determined by the equilibrium potentials of the ions and their permeabilities. In this case, Neuron X has equilibrium potential values of ENA = 50mV, EK = -90mV, and ECl = -55mV.

Given that Neuron X has a GNa that is 100 times as large as either GK or GCl, it means that the permeability of the membrane to sodium ions (Na+) is much higher compared to potassium ions (K+) and chloride ions (Cl-).

The resting membrane potential (Vm) can be approximated using the Goldman-Hodgkin-Katz equation, which takes into account the equilibrium potentials and permeabilities of the ions:

Vm = (PNa * ENa + PK * EK + PCl * ECl) / (PNa + PK + PCl)

Since GNa is 100 times larger than GK or GCl, we can assume that the permeability of Na+ (PNa) is 100 times larger than PK or PCl. Therefore, the equation can be simplified to:

Vm = (100 * ENa + EK + ECl) / (100 + 1 + 1)

Substituting the given values, we get:

Vm = (100 * 50mV + (-90mV) + (-55mV)) / (100 + 1 + 1)

Vm = (5000mV - 90mV - 55mV) / 102

Vm = 4855mV / 102

Vm ≈ 47.55mV

Therefore, the approximate value of the resting membrane potential (Vm) for Neuron X is approximately 47.55mV.

Learn more about resting membrane potential here:

https://brainly.com/question/33730682

#SPJ14