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Answer :
To determine the volume of hydrogen gas produced from [tex]\(38.6 \times 10^{23}\)[/tex] aluminum atoms, we can follow these steps:
1. Understand Avogadro's Number: Avogadro's number is [tex]\(6.022 \times 10^{23}\)[/tex] atoms/molecules per mole. This number helps us convert between the number of atoms and the number of moles.
2. Convert Aluminum Atoms to Moles:
- You have [tex]\(38.6 \times 10^{23}\)[/tex] aluminum atoms.
- To find the number of moles of aluminum, divide the number of atoms by Avogadro's number:
[tex]\[
\text{Moles of aluminum} = \frac{38.6 \times 10^{23}}{6.022 \times 10^{23}} \approx 6.41 \text{ moles}
\][/tex]
3. Use the Balanced Chemical Equation:
- The balanced chemical equation is:
[tex]\[
2 \text{Al} + 6 \text{HCl} \rightarrow 2 \text{AlCl}_3 + 3 \text{H}_2
\][/tex]
- According to this equation, 2 moles of aluminum produce 3 moles of hydrogen gas ([tex]\(H_2\)[/tex]).
4. Calculate Moles of Hydrogen Produced:
- Since 2 moles of aluminum produce 3 moles of hydrogen, use the ratio [tex]\( \frac{3}{2} \)[/tex] to find the moles of hydrogen:
[tex]\[
\text{Moles of hydrogen} = \left(\frac{3}{2}\right) \times 6.41 \approx 9.61 \text{ moles}
\][/tex]
5. Convert Moles of Hydrogen to Volume:
- At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.
- Therefore, the volume of hydrogen gas is:
[tex]\[
\text{Volume of hydrogen} = 9.61 \times 22.4 \approx 215.37 \text{ liters}
\][/tex]
So, the volume of hydrogen gas produced is approximately 215.37 liters.
1. Understand Avogadro's Number: Avogadro's number is [tex]\(6.022 \times 10^{23}\)[/tex] atoms/molecules per mole. This number helps us convert between the number of atoms and the number of moles.
2. Convert Aluminum Atoms to Moles:
- You have [tex]\(38.6 \times 10^{23}\)[/tex] aluminum atoms.
- To find the number of moles of aluminum, divide the number of atoms by Avogadro's number:
[tex]\[
\text{Moles of aluminum} = \frac{38.6 \times 10^{23}}{6.022 \times 10^{23}} \approx 6.41 \text{ moles}
\][/tex]
3. Use the Balanced Chemical Equation:
- The balanced chemical equation is:
[tex]\[
2 \text{Al} + 6 \text{HCl} \rightarrow 2 \text{AlCl}_3 + 3 \text{H}_2
\][/tex]
- According to this equation, 2 moles of aluminum produce 3 moles of hydrogen gas ([tex]\(H_2\)[/tex]).
4. Calculate Moles of Hydrogen Produced:
- Since 2 moles of aluminum produce 3 moles of hydrogen, use the ratio [tex]\( \frac{3}{2} \)[/tex] to find the moles of hydrogen:
[tex]\[
\text{Moles of hydrogen} = \left(\frac{3}{2}\right) \times 6.41 \approx 9.61 \text{ moles}
\][/tex]
5. Convert Moles of Hydrogen to Volume:
- At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.
- Therefore, the volume of hydrogen gas is:
[tex]\[
\text{Volume of hydrogen} = 9.61 \times 22.4 \approx 215.37 \text{ liters}
\][/tex]
So, the volume of hydrogen gas produced is approximately 215.37 liters.
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