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A cannon of mass 1060 kg fires a bullet. The bullet gains a velocity of 141 m/s. The velocity gain of the cannon due to recoil is 2 m/s. What is the mass of the bullet?

Answer :

The mass of the bullet is approximately 6.25 kg.

According to the law of conservation of momentum, the total momentum before firing the bullet is equal to the total momentum after firing the bullet. In this case, the momentum of the cannon and the bullet before firing is zero because they are at rest.

After firing, the cannon gains a velocity of 2 m/s in the opposite direction, and the bullet gains a velocity of 141 m/s in the forward direction.

Let's use the momentum equation to find the mass of the bullet:

Initial momentum = 0 (both cannon and bullet are at rest)

Final momentum = Mass of the cannon * Final velocity of the cannon + Mass of the bullet * Final velocity of the bullet

Final momentum = 1060 kg * (-2 m/s) + Mass of the bullet * 141 m/s

Now, equate the initial and final momenta:

0 = -2120 kg m/s + 141 m/s * Mass of the bullet

Solving for Mass of the bullet:

Mass of the bullet * 141 m/s = 2120 kg m/s

Mass of the bullet = 2120 kg m/s / 141 m/s ≈ 6.25 kg

The mass of the bullet is approximately 6.25 kg.

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