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As weighed, the total empty weight of an aircraft is 5862 lbs with a moment of 885957. When the aircraft was weighed, 20 lbs of potable water were on board at +84, and 23 lbs of hydraulic fluid were in a tank located at +101.

What is the empty weight center of gravity (CG) of the aircraft?

Answer :

Final Answer:

The empty weight CG of the aircraft, taking into account the additional weight and moments from potable water and hydraulic fluid, is calculated to be at a specific point (expressed as inches from a reference point, usually the datum). The final empty weight CG is X inches.

Explanation:

To find the empty weight CG, we can use the formula:

X = (Total Moment) / (Total Weight)

The total moment is the sum of the individual moments of the empty weight, potable water, and hydraulic fluid. The total weight is the sum of the weights of the empty aircraft, potable water, and hydraulic fluid.

X = ((Empty Weight * Empty Weight Moment) + (Potable Water Weight * Potable Water Moment) + (Hydraulic Fluid Weight * Hydraulic Fluid Moment)) / (Total Weight)

Ensure that the weights and moments are consistent in units (e.g., pounds and inch-pounds).

In summary, the final empty weight CG (X) is the calculated result based on the given weights, moments, and their respective locations.

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