We appreciate your visit to I arrive home to find that my 50 foot by 40 foot basement has 18 inches of water in it If 1 cubic foot contains. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Answer:
22.35 hours
Step-by-step explanation:
We given that
Length of basement=50 foot
Breadth of basement =40 foot
Height of water in basement =18 inches
We have to calculate number of hours to remove the water from the basement
We know that 1 inch= 0.083 foot
18 inches =[tex]18\times 0.083[/tex]=1.494 foot
Volume of water in basement =[tex]50\times40\times 1.494[/tex]
Volume of water in basement =2988 cubic foot
We are given that 1 cubic foot =7.48 gallons
2988 cubic foot=[tex]7.48\times2988=22350.24 gallons[/tex]
Volume of water in basement =22350.24 gallons
In one hour, water can remove by pumping=1000 gallons
Time taken to remove 1 gallon of water by pumping =[tex]\frac{1}{1000}[/tex]
Time taken to remove 22350.24 gallons of water by pumping =[tex]\frac{22350.24}{1000}=22.35024[/tex]=22.35 hours
Hence, It will take 22.35 hours to remove the water from my basement .
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Rewritten by : Barada
First convert all your measurents into inches 600in, 480in,18in then multiply them to get 5184000 cubic inches, convert cubic inches to gallons and you have 22441US gal lqd divide 22441 by 1000 and it will take you 22.441 hours
