In a shipment of 15 room air conditioners, there are 5 with defective thermostats. Two air conditioners will be randomly selected (without replacement) and inspected. What is the probability that the selected two are both defective? Round your answer to four decimal places.

Question

High School

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Answer :

Yogeshkumari Yogeshkumari · Answer 1 · 2024-12-03T01:49:24-05:00

The probability of both selected room air conditioners are defective is equal to 0.0952 rounded to four decimal places.

Total number of room air conditioners in shipment = 15

Number of defective room air conditioners = 5

The probability of the first air conditioner being defective is 5/15.

Since there are 5 defective air conditioners out of a total of 15.

After one air conditioner has been inspected,

There will be 4 defective air conditioners left out of a total of 14.

The probability of the second air conditioner also being defective, given that the first one was defective, is 4/14.

Probability of both air conditioners being defective.

Multiply probability of first air conditioner being defective by probability of second air conditioner being defective.

Given by first one was defective,

P(both defective) = (5/15) x (4/14)

Simplifying this expression ,

P(both defective) = 2/21

Therefore, the probability that the selected two air conditioners are both defective is 0.0952 rounded to four decimal places.

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