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A 13 kg log is being dragged along flat ground by a 114 N force at an angle of 45 degrees. If the log accelerates at a rate of [tex]0.72 \, \text{m/s}^2[/tex], what is the normal force acting on the log?

1) 40 N
2) 60 N
3) 80 N
4) 100 N

Answer :

Final answer:

The normal force acting on the log, given the parameters provided, is approximately 46.8 N. There might be a discrepancy in the question as the calculated normal force does not match with the given options.

Explanation:

The subject of this question is Physics, specifically dealing with forces and acceleration. Firstly, we need to calculate the vertical component of the 114 N force. Since the force is applied at a 45 degrees angle, the vertical and horizontal components of the force are equal. Therefore, the vertical component is just 114 N * sin(45°), which equals to approximately 80.6 N.

Next, we calculate the weight of the log, which is its mass times the acceleration due to gravity: 13 kg * 9.8 m/s² = 127.4 N. The normal force is the weight of the log minus the upward force applied to it, which is 127.4 N - 80.6 N. Therefore, the normal force acting on the log is approximately 46.8 N. Since 46.8 N is not listed in the options provided, there may be a discrepancy in the question itself, or additional forces at play that have not been taken into account in the question.

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