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Draw a Punnett Square for this test cross:

- Genotype 1: EB eb; AP ap
- Genotype 2: eb eb; ap ap

Using your Punnett Square as a reference, explain how this test cross will allow you to verify that the heterozygous individual produced all four possible gamete types (EB AP, EB ap, eb AP, eb ap) in equal frequencies during meiosis due to independent assortment.

Answer :

In the Punnett Square above, we can see that each of the four possible gamete types appears in equal frequency in the offspring, with each genotype occurring twice. This supports the idea that the heterozygous individual produced all four gamete types in equal frequencies during meiosis due to independent assortment.

E B b

e b b

The Punnett Square for the test cross between EB eb; AP ap X eb eb; ap ap would look like this:

eb eb

AP APEb/bap APEb/bap

ap apeb/bap apeb/bap

By performing a test cross between a heterozygous individual (EB eb; AP ap) and a homozygous recessive individual (eb eb; ap ap), we can determine the frequency at which the heterozygous individual produces each of the four possible gamete types (EB AP, EB ap, eb AP, eb ap). If the heterozygous individual produces these gamete types in equal frequencies due to independent assortment, we would expect each of the four possible genotypes to be equally represented in the offspring.

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