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Two arithmetic progressions (APs) have the same first and last terms. The first AP has 21 terms with a common difference of 9. How many terms does the other AP have if its common difference is 4?

Answer :

The number of terms of the second arithmetic progression is 46.

How to find the number of terms of an arithmetic progression?

The two arithmetic progression have the same first and last terms.

The first arithmetic progression has 21 terms with a common difference of 9.

The second arithmetic progression have common difference of 4.

Therefore,

using the first arithmetic progression,

a + (n - 1)d = nth term

a + 20(9) = last term

last term = a + 180

using the second arithmetic progression,

a + (n - 1)d = nth term

They have the same last and first term,

Hence,

a + 180 = a + (n - 1)4

a + 180 = a + 4n - 4

180 + 4 = 4n

184 = 4n

n = 184 / 4

n = 46

Therefore, the number of terms is 46

learn more on arithmetic progression(AP) here: https://brainly.com/question/16894868

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