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Answer :
The number of terms of the second arithmetic progression is 46.
How to find the number of terms of an arithmetic progression?
The two arithmetic progression have the same first and last terms.
The first arithmetic progression has 21 terms with a common difference of 9.
The second arithmetic progression have common difference of 4.
Therefore,
using the first arithmetic progression,
a + (n - 1)d = nth term
a + 20(9) = last term
last term = a + 180
using the second arithmetic progression,
a + (n - 1)d = nth term
They have the same last and first term,
Hence,
a + 180 = a + (n - 1)4
a + 180 = a + 4n - 4
180 + 4 = 4n
184 = 4n
n = 184 / 4
n = 46
Therefore, the number of terms is 46
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