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Answer :
Final answer:
The ball is in motion for around 3.3 seconds. The initial horizontal velocity is about 29.4 m/s, which remains constant before hitting the ground. The final vertical velocity isn't provided in the options.
Explanation:
The ball's motion involves both vertical and horizontal components. Given the details in the question, we first determine the total time the ball is in motion (Part 1). The time is completely dependent on vertical motion. Using the height of the building(53.5m) and the gravitational acceleration(9.8m/s²) we calculate the time using the formula√(2h/g), giving us approximately 3.3 seconds (A).
For Part 2, we calculate the initial velocity of the ball. This velocity is purely horizontal and can be found by dividing the horizontal distance the ball travels before it hits the ground (97.3m) by the time obtained in Part 1, yielding approximately 29.4m/s (C).
For Part 3, because there is no horizontal acceleration acting on the ball, its horizontal velocity remains unchanged, so The x-component of its velocity just before striking the ground is the same as its initial velocity, 29.4 m/s (C).
Lastly, in order to find the y-component of its velocity just before it strikes the ground (Part 4), we multiply gravity (9.8 m/s²) by the time in free fall (3.3 seconds) which gives us approximately 32.34 m/s, this is not an option in the provided answers.
Learn more about Projectile Motion here:
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