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Answer :
The maximum value for the force of friction is given by:
[tex]F_{max}=\mu_sN[/tex]
Where [tex]\mu_s[/tex] is the static friction between the body and the surface and N is the normal force on the body. Using the free body diagram, we know that:
[tex]N=mg[/tex]
Replacing this and solving:
[tex]F_{max}=\mu_s mg\\F_{max}=0.38*36kg*9.8\frac{m}{s^2}\\F_{max}=134.06N[/tex]
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Answer:
value of fs,max under the circumstances is
f = 42.56 N
Explanation:
The formula is µ = f / N, where µ is the coefficient of friction, f is the amount of force that resists motion, and N is the normal force. Normal force is the force at which one surface is being pushed into another.
So f = µN
f = 0.380 * 112
f = 42.56 N
