Answer :

We must utilise the information given to compute the molar mass of the acid and then compare it to the molar masses of other known acids in order to identify the acid in the given solution.

First, we can determine how much acid is present in 100 g of the solution: 75 g acid is equal to 100 g of solution. The density of the solution can then be used to determine the volume of 75 g of acid: 75 g x 1.57 g/mL = 47.77 mL. The moles of acid contained in 47.77 mL of the solution can now be determined using the molarity equation: Molarity equals litres of solution times moles of solute. 12.0 M = (47.77 mL x 1000 mL/L moles of acid = 0.57324 mol) moles of acid. We can determine the acid's molar mass by computing: Molar mass is equal to the product of mass and moles. Molar mass is 75 g divided by 0.57324 mol, or 130.94 g/mol. The substance with the closest molar mass to 130.94 g/mol is phosphoric acid (H3PO4) of 98.00 g/mol in mass. As a result, the acid in the solution is probably a combination of phosphoric acid and another acid.

Learn more about the acid here:

https://brainly.com/question/24784580

#SPJ4

Thanks for taking the time to read A 12 0 M acid solution that contains 75 0 acid by mass has a density of 1 57 g mL What is the identity. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada