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Answer :
													Sure! To find the pressure in a 5.00 L tank with 7.90 moles of oxygen at 39.3 °C, we can use the Ideal Gas Law, which is given by the formula:
[tex]\[ PV = nRT \][/tex]
Where:
- [tex]\( P \)[/tex] is the pressure in atmospheres
- [tex]\( V \)[/tex] is the volume in liters
- [tex]\( n \)[/tex] is the number of moles of the gas
- [tex]\( R \)[/tex] is the Ideal Gas Constant, which is 0.0821 L atm/mol K
- [tex]\( T \)[/tex] is the temperature in Kelvin
Here are the steps to solve the problem:
1. Convert the Temperature to Kelvin:
The given temperature is 39.3 °C. To convert degrees Celsius to Kelvin, you add 273.15:
[tex]\[ T = 39.3 + 273.15 = 312.45 \, \text{K} \][/tex]
2. Apply the Ideal Gas Law:
We know the following values:
- [tex]\( n = 7.90 \)[/tex] moles
- [tex]\( V = 5.00 \)[/tex] L
- [tex]\( R = 0.0821 \)[/tex] L atm/mol K
- [tex]\( T = 312.45 \)[/tex] K
Substituting these values into the formula [tex]\( PV = nRT \)[/tex] and solving for [tex]\( P \)[/tex]:
[tex]\[ P = \frac{nRT}{V} \][/tex]
[tex]\[ P = \frac{7.90 \times 0.0821 \times 312.45}{5.00} \][/tex]
3. Calculate the Pressure:
Compute the pressure [tex]\( P \)[/tex]:
[tex]\[ P \approx 40.53 \, \text{atm} \][/tex]
So, the pressure in the tank is approximately 40.53 atm.
												
											[tex]\[ PV = nRT \][/tex]
Where:
- [tex]\( P \)[/tex] is the pressure in atmospheres
- [tex]\( V \)[/tex] is the volume in liters
- [tex]\( n \)[/tex] is the number of moles of the gas
- [tex]\( R \)[/tex] is the Ideal Gas Constant, which is 0.0821 L atm/mol K
- [tex]\( T \)[/tex] is the temperature in Kelvin
Here are the steps to solve the problem:
1. Convert the Temperature to Kelvin:
The given temperature is 39.3 °C. To convert degrees Celsius to Kelvin, you add 273.15:
[tex]\[ T = 39.3 + 273.15 = 312.45 \, \text{K} \][/tex]
2. Apply the Ideal Gas Law:
We know the following values:
- [tex]\( n = 7.90 \)[/tex] moles
- [tex]\( V = 5.00 \)[/tex] L
- [tex]\( R = 0.0821 \)[/tex] L atm/mol K
- [tex]\( T = 312.45 \)[/tex] K
Substituting these values into the formula [tex]\( PV = nRT \)[/tex] and solving for [tex]\( P \)[/tex]:
[tex]\[ P = \frac{nRT}{V} \][/tex]
[tex]\[ P = \frac{7.90 \times 0.0821 \times 312.45}{5.00} \][/tex]
3. Calculate the Pressure:
Compute the pressure [tex]\( P \)[/tex]:
[tex]\[ P \approx 40.53 \, \text{atm} \][/tex]
So, the pressure in the tank is approximately 40.53 atm.
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