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Answer :
The merge list's function can handle these cases and provide the expected results.
To merge two linked lists, we can define a function in Python that takes in two linked list objects as parameters. Let's call this function merge_lists. Here's an example implementation:
1. Create a new function called merge lists that takes in two linked list objects as parameters: L1 and L2.
2. Inside the function, check if either L1 or L2 is an empty list. If either is empty, return the other list as the merged result. This accounts for cases (a) and (b) mentioned in the question.
3. If both L1 and L2 are non-empty lists, we need to traverse L1 to the end and append L2 to it. To do this, set a current variable to the head of L1.
4. Traverse the L1 list until the last node is reached. At each node, update the current variable to the next node.
5. Once the last node of L1 is reached, set the next pointer of this node to the head of L2. This attaches L2 to the end of L1.
6. Finally, set the head of L2 to None, making it an empty list.
Here's the code for the merge_lists function:
```python
def merge_lists(L1, L2):
if L1 is None:
return L2
if L2 is None:
return L1
current = L1
while current.next is not None:
current = current.next
current.next = L2
L2 = None
return L1
```
Let's test this function with the given example and additional cases:
(a) Merging L1 and L2 when L1 is an empty list:
- L1: None
- L2: 2 -> 4 -> 6 -> 8 -> 10
- Expected result: 2 -> 4 -> 6 -> 8 -> 10
(b) Merging L1 and L2 when L2 is an empty list:
- L1: 1 -> 3 -> 5
- L2: None
- Expected result: 1 -> 3 -> 5
(c) Merging L1 and L2 when both L1 and L2 are empty lists:
- L1: None
- L2: None
- Expected result: None
The merge lists function can handle these cases and provide the expected results.
To know more about cases visit:
https://brainly.com/question/13391617
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