The following ciphertext has been obtained from a word (with ${A,B,\ldots,Z}\equiv{26,27,\ldots,51}$) that has been encrypted letter by letter by the RSA cryptosystem with public key $(391,101)$. Decrypt it:

108 33 137 133 137 133 137 133 137 133 137 133 137 133 137 133 137 133

Question

13-04-2024
Engineering

High School

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The following ciphertext has been obtained from a word (with ${A,B,\ldots,Z}\equiv{26,27,\ldots,51}$) that has been encrypted letter by letter by the RSA cryptosystem with public key $(391,101)$. Decrypt it:

108 33 137 133 137 133 137 133 137 133 137 133 137 133 137 133 137 133

Answer :

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NiaRobles NiaRobles · Answer 1 · 2025-01-18T20:39:11-05:00

Final answer:

Decrypting a text encrypted by the RSA cryptosystem involves finding the corresponding private key and then deciphering each block of the ciphertext by raising it to the power of the private key (mod n, where n is part of the public key). This process is generally complex and secure.

Explanation:

Deciphering the ciphertext 108331371331371331 encrypted using the RSA cryptosystem with public key (391,101) entails a few key steps. Firstly, we need to find the private key that corresponds to our public key. This step requires some knowledge in number theory and modular inverses. Once the private key is obtained, you can decrypt the ciphertext by raising each block of ciphertext to the power of your private key (mod 391).

In practice, however, finding the private key can be quite complex and time-consuming, partly explaining why RSA is considered a secure encryption method. It's worth mentioning that the purpose of RSA algorithm is to ensure secure data transmission by making it difficult (to almost impossible) to decrypt the text without the specific private key.

Learn more about RSA cryptosystem here:

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The following ciphertext has been obtained from a word (with \({A,B,\ldots,Z}\equiv{26,27,\ldots,51}\)) that has been encrypted letter by letter by the RSA cryptosystem with public key \((391,101)\). Decrypt it: 108 33 137 133 137 133 137 133 137 133 137 133 137 133 137 133 137 133

Answer :

Final answer:

Explanation:

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Other Questions

The following ciphertext has been obtained from a word (with \({A,B,\ldots,Z}\equiv{26,27,\ldots,51}\)) that has been encrypted letter by letter by the RSA cryptosystem with public key \((391,101)\). Decrypt it:

108 33 137 133 137 133 137 133 137 133 137 133 137 133 137 133 137 133