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Answer :
Answer:
2x^4 - 9x^3 -8x^2 + 15x
Step-by-step explanation:
(x^2-5x)(2x^2+x-3) distribute first
2x^4
x^2 + x = x^3
5 * 2x^2 x= 10x^3
5x^1+1 = 5x^2
5 * 3x = 15x Put them all together
2x^4 + x^3 - 3x^2 - 10x^3 - 5x^2 + 15x Like terms
2x^4 + x^3 -10x^3 - 3x^2- 5x^2 + 15x Add similar terms
= 2x^4 + x^3 - 10x^3 - 8x^2 + 15x more adding terms
2x^4 - 9x^3 -8x^2 + 15x
Hope my answer has helped you, if not i'm sorry.
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Rewritten by : Barada
For this case we must multiply the following expression:
[tex](x ^ 2-5x) (2x ^ 2 + x-3)[/tex]
We apply distributive property term to term taking into account that:
[tex]+ * - = -\\- * - = +\\x ^ 2 * 2x ^ 2 + x ^ 2 * x-x ^ 2 * 3-5x * 2x ^ 2-5x * x + 5x * 3 =[/tex]
For powers of the same base, we place the same base and add the exponents:
[tex]2x ^ 4 + x ^ 3-3x ^ 2-10x ^ 3-5x ^ 2 + 15x =[/tex]
We add similar terms:
[tex]2x ^ 4-9x ^ 3-8x ^ 2 + 15x[/tex]
Answer:
OPTION D
[tex]2x ^ 4-9x ^ 3-8x ^ 2 + 15x[/tex]
