We appreciate your visit to How many moles of NaCl are present in 600 mL of a 1 55 M NaCl solution. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Answer:
The answer is 2.583 moles
Explanation:
molarity is defined as the number of moles divided by the volume of the solution, as follows:
M = nmoles/Volume
Clearing the nmoles:
600 mL = 0.6 L
nmoles = MxVolume = 1.55 mol/L x 0.6 L = 2.583 moles
Thanks for taking the time to read How many moles of NaCl are present in 600 mL of a 1 55 M NaCl solution. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
The moles of NaCl are present in 600 ml of a 1.55 m NaCl solutions
nmoles= 2.583 moles
What moles of NaCl are present in 600 ml of a 1.55 m nacl solutions?
Question Parameter(s):
Generally, the equation for the Molarity is mathematically given as
M = nmoles/Volume
Where
n=600ml
n=0.6L
In conclusion
nmoles = MxVolume
nmoles= 1.55 mol/L x 0.6 L
nmoles= 2.583 moles
Read more about Chemical reaction
https://brainly.com/question/16416932
