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Answer :
Answer:
[tex]a=-2.22m/s^2[/tex]
Explanation:
the information we have is:
initial velocity: [tex]v_{i}=12m/s[/tex]
final velocity: [tex]v_{f}=2m/s[/tex]
and the time: [tex]t=4.5s[/tex]
We need to find the acceleration of the car.
For this we use formula to calculate the acceleration given the information we were given:
[tex]a=\frac{v_{f}-v_{i}}{t}[/tex]
acceleration is equal to the difference between the final velocity and the initial velocity divided by time.
We substitute all the known values:
[tex]a=\frac{2m/s-12m/s}{4.5s}\\ \\a=\frac{-10m/s}{4.5s}\\ \\a=-2.22m/s^2[/tex]
the acceleration is [tex]-2.22m/s^2[/tex]
the result is negative because the car is slowing down.
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