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Farmer Ed has 3,500 meters of fencing and wants to enclose a rectangular plot that borders a river. If Farmer Ed does not fence the side along the river, what is the largest area that can be enclosed?

Answer :

Answer:

Because it is a rectangle, the area is expressed as A = xy, or length times width.

Step-by-step explanation:

Because it is next to the river, he only needs to fence three sides, so F = x + 2y.

Knowing the amount of fencing available is 7500m, we get:

7500 = x + 2y solve for x

x = 7500 - 2y substitute into the area equation

A = (7500 - 2y)y distribute

A = -2y2 +7500y

You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = -b/2a = -7500/[2(-2)] = 1875

x = 7500 - 2(1875) = 3750

A = 3750(1875) = 7,031,250 m2

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Rewritten by : Barada

If Farmer Ed has 3,500 meters of​ fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not fence the side along the​ river, Then 7,031,250 is the largest area that can be​ enclosed.

What is Rectangle?

A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles (90°).The opposite sides of a rectangle are equal and parallel.

As it is next to the river, he only needs to fence three sides, so F = x + 2y.

Knowing the amount of fencing available is 7500m, we get:

7500 = x + 2y

solve for x

x = 7500 - 2y

substitute into the area equation

A = (7500 - 2y)y

Distribute

A = -2y2 +7500y

You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = -b/2a = -7500/[2(-2)] = 1875

x = 7500 - 2(1875) = 3750

A = 3750(1875) = 7,031,250 m².

Hence 7031250 is the largest area that can be​ enclosed.

To learn more on Rectangles click:

https://brainly.com/question/15019502

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