Answer :

Answer:

The steps are shown below. From here, we can write:

[tex]\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1+\frac{0}{x+3} \\ \\ \therefore \boxed{\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1}[/tex]

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Rewritten by : Barada

Answer:

x^2-5x+1

Step-by-step explanation:

this is correct