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How many moles are there in 141 g of [tex]$Al_2O_3$[/tex]?

Answer :

Answer: no. Moles= 1.382moles

Explanation:

No. Of moles = mass/molar mass

NB : molar mass Al2O3= (27×2)+(16×3)= 102

n= 141/102 = 1.382moles

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