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Answer :
Using the ideal gas law PV = nRT, we calculated the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K. By substituting the given values into the formula, we found the pressure to be 28.2 kPa.
Use PV = nRT and R = 8.314 L kPa / mol K to solve.
We will use the ideal gas law formula: PV = nRT.
P is the pressure in kPa
V is the volume, which is 35.5 L
n is the number of moles, which is 0.540 mol
R is the ideal gas constant, which is 8.314 L kPa / mol K
T is the temperature, which is 223 K
Rearrange the formula to solve for P:
P = (nRT) / V
Substitute the given values into the equation:
P = (0.540 mol × 8.314 L kPa / mol K × 223 K) / 35.5 L
Calculate the value:
P = (1002.3362) / 35.5
P = 28.2 kPa
Therefore, the pressure of the gas is 28.2 kPa.
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Answer:
- 0.0443 atm
Explanation:
1) Data:
a) n = 0.540 mol
b) V = 35.5 liter
c) T = 223 K
2) Formula:
- Ideal gas equation: PV = nRT
Where,
- P = pressure
- V = volume
- n = number of moles
- T = absolute temperature (kelvin scale)
- R = universal gas constant = 0.08203 atm-liter/K-mol
3) Calculations:
- Solve for P
PV = nRT ⇒ P = nRT/V
- Substitute and compute:
P = 0.540 mol × 0.08206 atm-liter/K-mol × 223 K / 35.5 liter
P = 0.0443 atm (you must use 3 significant figures).
