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Answer :
Answer:
The coefficient of static friction between the bookcase and the floor, μₓ = 0.3292
Explanation:
Given data,
The mass of the bookcase, m = 181 kg
The static frictional force of the bookcase, Fₓ = 584 N
The gravitational normal force acting on the bookcase is, F = m g
= 181 x 9.8
= 1773.8 N
The formula for static frictional force is
Fₓ = μₓ F
Where μₓ - the coefficient of the static friction
μₓ = Fₓ / F
= 584 N / 1773.8 N
= 0.3292
Hence, the coefficient of static friction between the bookcase and the floor, μₓ = 0.3292
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