Middle School

We appreciate your visit to Initially there were 197 weeds at a park growing at a rate of 25 each week The function representing weekly weed growth is tex f. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Initially, there were 197 weeds at a park, growing at a rate of 25% each week. The function representing weekly weed growth is [tex]f(x) = 197(1.25)^x[/tex]. Rewrite the function to show how quickly the weeds grow each day, and calculate this rate as a percentage.

A. [tex]f(x) = 197(1.25)^{7x}[/tex]; grows at a rate of approximately 2.5% daily
B. [tex]f(x) = 197(1.25^{7})^x[/tex]; grows at a rate of approximately 4.77% daily
C. [tex]f(x) = 197(1.03)^x[/tex]; grows at a rate of approximately 0.3% daily
D. [tex]f(x) = 197(1.03)^{7x}[/tex]; grows at a rate of approximately 3% daily

Answer :

Answer:

none of the above

f(x) ≈ 197·1.03^x; approximately 3% daily

Step-by-step explanation:

If we let x represent days, then x/7 represents weeks and we can rewrite f(x) as ...

f(x/7) = 197·1.25^(x/7) = 197·(1.25^(1/7))^x

f(x) ≈ 197·1.03^x

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The daily multiplier of 1.03 represents a daily growth rate of

1.03 -1 = .03 = 3%

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These answers are not found among the offered choices:

  • f(x) = 197·1.03^x
  • 3% daily growth

Thanks for taking the time to read Initially there were 197 weeds at a park growing at a rate of 25 each week The function representing weekly weed growth is tex f. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada

The correct answer to this question is D.